Arithmetic Sequence

A sequence a{n} is called an arithmetic sequence (or arithmetic progression) if it consists of numbers arranged in such a way that the difference between any term and the one before it is constant.

What is an arithmetic sequence

A sequence $a_{n}$ is called an arithmetic sequence (or arithmetic progression) if it consists of numbers arranged in such a way that the difference between any term and the one before it is constant. It is characterized by terms of the form:

\[a_{1} , a_{2} , \ldots , a_{n} \text{with} a_{n} - a_{n - 1} = d\]
  • By convention, the first term of an arithmetic progression is typically indexed with $n = 1.$
  • $d$ represents the difference between two consecutive terms in an arithmetic progression, and it is known as the common difference.
  • If $d > 0$, the progression is increasing.
  • If $d < 0$, the progression is decreasing.
  • If $d = 0$, the progression is constant.

Let’s consider, for example, the sequence of non-negative even numbers:


An arithmetic sequence can also be defined using a recursive formula:

\[a_{n} = a_{1} + n \cdot d \text{where} a_{1} , d \in \mathbb{R}\]

An arithmetic progression exhibits a characteristic stepwise pattern, where the height of each step corresponds to the common difference between consecutive terms in the sequence.


In an arithmetic progression, each term $a_{n}$ is obtained by adding the first term $a_{1}$ to the product of the common difference $d$ and $( n - 1 )$. This gives the general formula for the $n$-th term:

\[a_{n} = a_{1} + ( n - 1 ) \cdot d \text{for} n \geq 1\]

This formula allows you to compute any term in the sequence directly, without listing all the previous ones.

Example

Let’s define an arithmetic sequence with first term $a_{1} = 2$ and common difference $d = 3$. We use the formula:

\[a_{n} = a_{1} + ( n - 1 ) \cdot d\]

Plug in the values:

\[a_{n} = 2 + ( n - 1 ) \cdot 3\]

Now calculate the first few terms:

  • $a_{1} = 2$
  • $a_{2} = 2 + 1 \cdot 3 = 5$
  • $a_{3} = 2 + 2 \cdot 3 = 8$
  • $a_{4} = 2 + 3 \cdot 3 = 11$
  • $a_{5} = 2 + 4 \cdot 3 = 14$

The resulting sequence is: \(2 , 5 , 8 , 11 , 14 , \ldots\)

Sum of $n$ terms of an arithmetic progression

The sum $S_{n}$ of the first $n$ terms $a_{1} , a_{2} , \ldots , a_{n}$ of an arithmetic progression is equal to the product of $n$ and the average of the first and last term:

\[S_{n} = n \cdot \frac{a_{1} + a_{n}}{2}\]

This formula allows you to quickly compute the total sum of a finite number of terms in an arithmetic progression. For example, consider the arithmetic progression of non-negative even numbers: \(2 , 4 , 6 , 8 , 10\)

We want to calculate the sum of the first 5 terms $( n = 5 ) .$ Using the formula, we have: \(S_{5} = 5 \cdot \frac{2 + 10}{2} = 5 \cdot 6 = 30\)

This illustrates the same reasoning behind Gauss’s trick: by pairing the first and last terms, you can quickly compute the total sum of an arithmetic progression.